Posted on: August 15, 2019 | Author: Odisha Job Alert | Category: Odisha Govt. Job

OSSC Recruitment for the Post of Food Safety Officer 2019.
Total Post :-  12
Vacancies Details :-
1- Food Safety Officer :-  12 (UR- 03, SC- 01, ST- 08)


Who Can Apply :-  All Odisha Candidates.
Gender :-  Both Male/female Apply.
Job Location :- Odisha.
Apply Mode :- Online.
Apply Start Date :- 14-08-2019.
Apply Last Date :- 13-09-2019.
Application Fee :-  Rs- 100/- (General/SEBC)
                                   SC/ST/PwD :- No Fee.
Mode of Payment :- Online.

Age :-   As On 01-01-2017.
For General Candidates :-  21 – 32 Years.
For SEBC/SC/ST/Women :-  21 – 37 Years.
For PwD Candidates :-  21 – 42 Years.


Qualification :-
Bachelor’s Degree in Food Technology or  Diary Technology or Biotechnology or  Oil Technology or Agricultural Science or  Veterinary Science or Bio-Chemistry or  Microbiology or  Master Degree in Chemistry or  Degree in Medicine With Knowledge in Computer Application.

Salary :-
Scale Pay- Rs-9,300 – Rs-34,800 + G.P. Rs-4200
Selection Process :-
1- Written Examination :-
The Examination Consists of two Papers.
Paper – I
   Exam. Type :- Objective Type.
   No. of Questions :- 100
   Full Mark’s :- 100 Mark
   Time :- 1 Hour 30 Minutes.
Subject :-
General Studies, English, Mathematics, Computer Application(Theory).


Paper- II
   Exam. Type :- Objective Type.
   No. of Questions :- 100
   Full Mark’s :- 100 Mark
   Time :- 1 Hour 30 Minutes.
Subject :-
   1- Food Safety Act & Rule (50 Marks)
   2- Chemistry (50 Marks)


N.B :-  There will be a Negative Marking of 0.25 Marks for Each Wrong Answer.


2- Computer Skill Test.
Full Mark’s :- 100 Mark.
Time :- 1 Hours.
Qualifying Mark’s :- 15 Mark
3- Document Verification.

Official Website  :-  Click Here

 


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